2x 2 6x 1 0.

$$ Factors = 6x \hspace{0.025in} and \hspace{0.025in} 2x+1 $$ The free online local maxima and minima calculator also find these answers but in seconds by saving you a lot of time. Critical points: Putting factors equal to zero: $$ 6x = 0 $$ $$ x = 0 $$ And. $$ 2x+1 =0 $$ $$ x = -\frac{1}{2} $$Dec 9, 2019 · It isn't easy to immediately see how $2x^2-1$ can factor (or if it can) but $2x^2 - 1 \equiv 2x^2 + 6\equiv 2(x^2 +3)$ so if we can find $-k^2 \equiv 3\pmod 7$ we can have a difference of squares. $3 \equiv -4.. $ and ... that was quick. So $2x^3+5x^2 + 6x + 1\equiv (2x^2-1)(x-1)$ $\equiv 2(x^2+3)(x-1)\equiv 2(x^2 -4)(x-1)$ $\equiv 2(x+2)(x-2 ... 2*x^2-(6*x-1)=0 . Step by step solution : Step 1 : Equation at the end of step 1 : 2x 2 - (6x - 1) = 0 Step 2 : Trying to factor by splitting the middle term 2.1 Factoring 2x 2-6x+1 The first term is, 2x 2 its coefficient is 2 . The middle term is, -6x its coefficient is -6 . The last term, "the constant", is +1 Factor out the GCF: 2x2 + 6x = 0. 2x(x + 3) = 0. 2x = 0. x = 0. x + 3 = 0. x = − 3. Answer link. x=-3" or "x=0 >"factor the quadratic" 2x (x+3)=0 "equate each factor to zero and solve for x" 2x=0rArrx=0 x+3=0rArrx=-3.Algebra. Solve by Factoring 2x^2-x-6=0. 2x2 − x − 6 = 0 2 x 2 - x - 6 = 0. Factor by grouping. Tap for more steps... (2x+3)(x −2) = 0 ( 2 x + 3) ( x - 2) = 0. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. 2x+3 = 0 2 x + 3 = 0. x−2 = 0 x - 2 = 0.

Step 2 : Trying to factor by splitting the middle term. 2.1 Factoring 9x2-6x+1. The first term is, 9x2 its coefficient is 9 . The middle term is, -6x its coefficient is -6 . The last term, "the constant", is +1. Step-1 : Multiply the coefficient of the first term by the constant 9 • 1 = 9. Step-2 : Find two factors of 9 whose sum equals the ...giải phương trình : \ (2x^2-6x-1=\sqrt {4x+5}\) - Hoc24. Đăng nhập Đăng ký. Lớp 9. Chủ đề. Chương I - Căn bậc hai. Căn bậc ba. Chương II - Hàm số bậc nhất. Chương III - Hệ hai phương trình bậc nhất hai ẩn. Chương IV - Hàm số y = ax^2 (a khác 0).

2.2 Solving x2+6x+1 = 0 by Completing The Square . Subtract 1 from both side of the equation : x2+6x = -1. Now the clever bit: Take the coefficient of x , which is 6 , divide by two, giving 3 , and finally square it giving 9. Add 9 to both sides of the equation : On the right hand side we have : -1 + 9 or, (-1/1)+ (9/1)

Steps Using the Quadratic Formula Steps for Completing the Square Steps Using Direct Factoring Method View solution steps Graph Graph Both Sides in 2D Graph in 2D Quiz Quadratic Equation x2+6x+1 = 0 Videos Evaluar expresiones con dos variables: fracciones y decimales Khan Academy Separar problemas de suma de números de 2 dígitos Khan Academyx2-6x-7=0 Two solutions were found : x = 7 x = -1 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-6x-7 The first term is, x2 its ... 2x2-6x-7=0 Two solutions were found : x = (6-√92)/4= (3-√ 23 )/2= -0.898 x = (6+√92)/4= (3+√ 23 )/2= 3.898 Step by step solution : Step 1 :Equation at the end ...(Bawalah turun pangkat 2 dalam x 2 sebagai koefisien, hapus x dalam -5x, dan ubah 19 menjadi 0) 2x + y 2 - 5 + 8y + 2xy 2 = 0 ... (6x + 1) (6x + 1)cos(3x 2 + x) 3. Untuk persamaan dengan variabel-variabel x, y, dan z, carilah (dz/dx) dan (dz/dy). Meskipun tidak biasa dalam kalkulus dasar, beberapa penerapan lanjut mungkin membutuhkan turunan ...Solve Using the Quadratic Formula x^2+6x-1=0. x2 + 6x − 1 = 0 x 2 + 6 x - 1 = 0. Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. Substitute the values a = 1 a = 1, b = 6 b = 6, and c = −1 c = - 1 into the quadratic formula and solve for x x. −6±√62 −4⋅ (1⋅−1) 2⋅1 - 6 ± 6 2 ...

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x2-6x-91=0 Two solutions were found : x = 13 x = -7 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-6x-91 The first term is, x2 its ... -x2-6x-91=0 Two solutions were found : x = (6-√-328)/-2=3+i√ 82 = -3.0000-9.0554i x = (6+√-328)/-2=3-i√ 82 = -3.0000+9.0554i Step by step solution : Step 1 ...

To complete the square when a is greater than 1 or less than 1 but not equal to 0, divide both sides of the equation by a. This is the same as factoring out the value of a from all other terms. As an example let's …9x2+6x+1=0 One solution was found : x = -1/3 = -0.333 Step by step solution : Step 1 :Equation at the end of step 1 : (32x2 + 6x) + 1 = 0 Step 2 :Trying to factor by ... 9x2+6x+1=4 Two solutions were found : x = -1 x = 1/3 = 0.333 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the ...Solution: The complex zero calculator can be writing the \ ( 4x^2 – 9 \) value as \ ( 2.2x^2- (3.3) \) Where, it is (2x + 3) (2x-3). For finding zeros of a function, the real zero calculator set the above expression to 0. Similarly, the zeros of a …Solve by Completing the Square x^2-6x-1=0 | Mathway Algebra Examples Popular Problems Algebra Solve by Completing the Square x^2-6x-1=0 x2 − 6x − 1 = 0 x 2 - 6 x - 1 = 0 Add 1 1 to both sides of the equation. x2 − 6x = 1 x 2 - 6 x = 1Precalculus. Factor 2x^2+6x+1. 2x2 + 6x + 1 2 x 2 + 6 x + 1. 2x2 + 6x+1 2 x 2 + 6 x + 1. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.Contoh Persamaan Eksponen. 1. 3 2x-3 = 81 x+5 → persamaan eksponen dengan pangkat mengandung variabel x. 2. (2x – 5) x = (2x – 5) 3x-4 → persamaan eksponen dengan basis dan pangkat mengandung variabel x. Jadi, dalam persamaan eksponen itu, bisa pangkatnya saja yang mengandung variabel atau bisa juga basis dan …

Kuadrat Sempurna dari x² + 2x - 1 = 0. Catatan: Contoh ini akan lebih sulit jika dikerjakan dengan cara faktorisasi persamaan kuadrat. ... ∴ Jadi, akar-akar persamaan kuadrat dari x² + 6x + 8 = 0 adalah x 1 = -2 dan x 2 = -4. Contoh 2. Hitung Akar Persamaan x² + 2x - 1 = 0 dengan Rumus ABC!d) La ecuación x2 +y2 = 2x representa una circunferencia de centro (1,0) y radio ... 1) El punto P = (1,1,0, π. 2. ,0) satisface el sistema dado por las tres ...Solve for x: y=-2x^2-6x+1 2x^2+6x+y-1=0 Use the quadratic formula with a=2, b=6, c=y-1 x=(-6 +-sqrt ((6)^2-4 (2)(y-1)))/4 This will give real numbers for x if 36-8y+8 >= 0 44>=8y y <= 11/2 The range is all reals less than or equal to 11/2. The interval (-oo, 5/2) Algebra . ScienceSolve the equation for x x. Tap for more steps... x = ± √7 2 + 3 2 x = ± 7 2 + 3 2 The result can be shown in multiple forms. Exact Form: x = ± √7 2 + 3 2 x = ± 7 2 + 3 2 Decimal Form: x = 2.82287565…,0.17712434… x = 2.82287565 …, 0.17712434 … A quadratic inequality is an equation of second degree that uses an inequality sign instead of an equal sign. Examples of quadratic inequalities are: x 2 – 6x – 16 ≤ 0, 2x 2 – 11x + 12 > 0, x 2 + 4 > 0, x 2 – 3x + 2 ≤ 0 etc.. Solving a quadratic inequality in Algebra is similar to solving a quadratic equation. The only exception is that, with quadratic equations, you …Simplify (2x-6) (2x+6) (2x − 6) (2x + 6) ( 2 x - 6) ( 2 x + 6) Expand (2x−6)(2x+ 6) ( 2 x - 6) ( 2 x + 6) using the FOIL Method. Tap for more steps... 2x(2x)+2x⋅6−6(2x)−6⋅ 6 2 x ( 2 x) + 2 x ⋅ 6 - 6 ( 2 x) - 6 ⋅ 6. Simplify and combine like terms. Tap for more steps... 4x2 − 36 4 x 2 - 36. Free math problem solver answers your ...$$ Factors = 6x \hspace{0.025in} and \hspace{0.025in} 2x+1 $$ The free online local maxima and minima calculator also find these answers but in seconds by saving you a lot of time. Critical points: Putting factors equal to zero: $$ 6x = 0 $$ $$ x = 0 $$ And. $$ 2x+1 =0 $$ $$ x = -\frac{1}{2} $$

x^2-6x-160. 2x{(x-6)}^{2} 3x^2-10x+8. Kembali ke atas. Bahasa Indonesia Tentang Math Solver; Soal-Soal yang Sering Ditemukan ...

Free functions range calculator - find functions range step-by-stepSolve Using the Quadratic Formula 2x^2-2x-1=0. 2x2 − 2x − 1 = 0 2 x 2 - 2 x - 1 = 0. Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. Substitute the values a = 2 a = 2, b = −2 b = - 2, and c = −1 c = - 1 into the quadratic formula and solve for x x. 2±√(−2)2 −4 ⋅(2⋅−1) 2⋅ ...x2 + y2 + 6x − 2y + 1 = 0 x 2 + y 2 + 6 x - 2 y + 1 = 0. Subtract 1 1 from both sides of the equation. x2 + y2 +6x−2y = −1 x 2 + y 2 + 6 x - 2 y = - 1. Complete the square for x2 +6x x 2 + 6 x. Tap for more steps... (x+3)2 −9 ( x + 3) 2 - 9. Substitute (x+3)2 − 9 ( x + 3) 2 - 9 for x2 +6x x 2 + 6 x in the equation x2 + y2 +6x−2y ...y = −2x2 + 6x − 1 y = - 2 x 2 + 6 x - 1. Find the properties of the given parabola. Tap for more steps... Direction: Opens Down. Vertex: (3 2, 7 2) ( 3 2, 7 2) Focus: (3 2, 27 8) ( 3 2, 27 8) Axis of Symmetry: x = 3 2 x = 3 2. Directrix: y = 29 8 y = 29 8. Select a few x x values, and plug them into the equation to find the corresponding y ...Limits. Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. 2x2-6x+4=0 Two solutions were found : x = 2 x = 1 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 - 6x) + 4 = 0 Step 2 : Step 3 :Pulling out like terms : 3.1 ... 3x2-6x+4=0 Two solutions were found : x = (6-√-12)/6=1-i/3√ 3 = 1.0000-0.5774i x = (6+√-12)/6=1+i/3√ 3 = 1.0000+0.5774i Step by step solution : Step 1 ...kx 2 + 2x + 1 = 0. It’s of the form of ax 2 + bx + c = 0. Where, a =k, b = 2, c = 1. For the given quadratic equation to have real roots D = b 2 – 4ac > 0. D = (2) 2 – 4(1)(k) > 0. ⇒ 4 – 4k > 0. ⇒ 4k < 4. ⇒ k < 1. The value of k should be lesser than 1 to have real and distinct roots. (ii) kx 2 + 6x + 1 = 0. Solution: Given, kx 2 ...Jika x 1 merupakan bilangan positif dan x 2 merupakan bilangan negatif, nilai 2x 1 + x 2 adalah-2; 5; 2; 0; Pembahasan: Mula-mula, kamu harus memfaktorkan persamaan kuadrat pada soal. x2 + 4x – 32 = 0. ⇔ (x + 8)(x – 4)=0. ⇔ x = -8 atau x = 4. Di soal tertulis bahwa x 1 merupakan bilangan positif dan x 2 merupakan bilangan negatif ...Solving exponential equations is pretty straightforward; there are basically two techniques: <ul> If the exponents... Read More Save to Notebook! Sign in Free equations calculator - solve linear, quadratic, polynomial, radical, exponential and logarithmic equations with all the steps. Type in any equation to get the solution, steps and graph

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Contoh Persamaan Eksponen. 1. 3 2x-3 = 81 x+5 → persamaan eksponen dengan pangkat mengandung variabel x. 2. (2x – 5) x = (2x – 5) 3x-4 → persamaan eksponen dengan basis dan pangkat mengandung variabel x. Jadi, dalam persamaan eksponen itu, bisa pangkatnya saja yang mengandung variabel atau bisa juga basis dan …

Solution, 3a. Solve Quadratic equation by completing square method. 2 x 2 + 6 x + 1 = 0. Subtract 1 from both sides of the equation. 2 x 2 + 6 x = − 1. Divide each term in 2 x 2 + 6 x = − 1 by 2 and simplify. x 2 + 3 x = − 1 2. To create a trinomial square on the left side of the equation, find a value that is equal to the squ...First, the expression needs to be rewritten as 2x^{2}+ax+bx-1. To find a and b, set up a system to be solved. a=-2 b=1 . Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. ... 2x^{2}-x-1=0 . Quadratic polynomial can be factored using the transformation ...Increased Offer! Hilton No Annual Fee 70K + Free Night Cert Offer! Rakuten is currently offering triple cash back at many merchants. There are also many merchants where you can earn increased rates for shopping in stores. Two merchants of i...Solve by Factoring 6x^2-2x=0. 6x2 − 2x = 0 6 x 2 - 2 x = 0. Factor 2x 2 x out of 6x2 −2x 6 x 2 - 2 x. Tap for more steps... 2x(3x−1) = 0 2 x ( 3 x - 1) = 0. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. x = 0 x = 0. 3x−1 = 0 3 x - 1 = 0. Set x x equal to 0 0.Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.Simplify (2x-1) (6x-7) (2x − 1) (6x − 7) ( 2 x - 1) ( 6 x - 7) Expand (2x−1)(6x− 7) ( 2 x - 1) ( 6 x - 7) using the FOIL Method. Tap for more steps... 2x(6x)+2x⋅−7−1(6x)− 1⋅−7 2 x ( 6 x) + 2 x ⋅ - 7 - 1 ( 6 x) - 1 ⋅ - 7. Simplify and combine like terms. Tap for more steps... 12x2 − 20x+7 12 x 2 - 20 x + 7. Free math ...Giải phương trình \(2x^2-6x-5(x-2)\sqrt{x+1}+10=0\) Theo dõi Vi phạm Toán 10 Chương 3 Bài 2 Trắc nghiệm Toán 10 Chương 3 Bài 2 Giải bài tập Toán 10 Chương 3 Bài 2. Trả lời (1) Điều kiện \(x \geq -1\). Phương trình đã cho tương đương vớiTo find the y-intercepts of a function, set the value of x to 0 and solve for y. What are the intercepts points of a function? The function intercepts points are the points at which the function crosses the x-axis or the y-axis.Step 2 : Trying to factor by splitting the middle term. 2.1 Factoring 9x2-6x+1. The first term is, 9x2 its coefficient is 9 . The middle term is, -6x its coefficient is -6 . The last term, "the constant", is +1. Step-1 : Multiply the coefficient of the first term by the constant 9 • 1 = 9. Step-2 : Find two factors of 9 whose sum equals the ...Explanation: Given - 2x2 − 6x +1 = 0 2x2 − 6x = −1 2x2 2 − 6x 2 = −1 2 x2 −3x = −1 2 x2 −3x + 9 4 = −1 2 + 9 4 (x − 3 2)2 = −2 +9 4 = 7 4 (x − 3 2) = ± √ 7 4 x = √ 7 4 + 3 2 x = − √7 4 + 3 2 Answer linkDetermine la solución de la siguiente ecuación cuadrática: $3x^2+6x-1=2x^2+13x-7$3 x 2+6 x −1=2 x 2+13 x −7. Respuesta correcta: x = 6; x = 1. 0. 0.Rearrange into the form: (x−4)2 +(y−3)2 = 22 to identify the centre (4,3) and radius 2 ... Find the equations of the circles that have centre (0,0) and touch the circle x2 + y2 − 8x − 6y + 24 = 0. This does not need calculus, just a theorem from euclidean geometry. The given circle has centre (4,3) and radius 1 unit.

Algebra. Solve by Factoring 6x^2+x-2=0. 6x2 + x − 2 = 0 6 x 2 + x - 2 = 0. Factor by grouping. Tap for more steps... (2x−1)(3x+2) = 0 ( 2 x - 1) ( 3 x + 2) = 0. If any individual …Solving exponential equations is pretty straightforward; there are basically two techniques: <ul> If the exponents... Read More Save to Notebook! Sign in Free equations calculator - solve linear, quadratic, polynomial, radical, exponential and logarithmic equations with all the steps. Type in any equation to get the solution, steps and graph2x2 − 6x − 1 = 0. http://www.tiger-algebra.com/drill/2x~2-6x-1=0/. 2x2-6x-1=0 Two solutions were found : x = (6-√44)/4= (3-√ 11 )/2= -0.158 x = (6+√44)/4= (3+√ 11 )/2= 3.158 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 - 6x) - 1 = 0 ...Instagram:https://instagram. firestone auto complete care near me Completing the square is a method that represents a quadratic equation as a combination of quadrilateral used to form a square. The basis of this method is to discover a special value that when added to both sides of the quadratic that will create a perfect square trinomial. That special value is found by evaluation the expression (b 2)2 where ... evil dead rise showtimes near century 14 vallejo Solving exponential equations is pretty straightforward; there are basically two techniques: <ul> If the exponents... Read More Save to Notebook! Sign in Free equations calculator - solve linear, quadratic, polynomial, radical, exponential and logarithmic equations with all the steps. Type in any equation to get the solution, steps and graph Solve an equation, inequality or a system. Example: 2x-1=y,2y+3=x. 1: 2: 3: 4: 5: 6: 7: 8: 9: 0., < > ≤: ≥ ^ √: ⬅: : F _ ÷ | (* / ⌫ A: ↻: x: y = +-G sugar nadya = 2x 2+3 – 2x 2+1 + 4x 2+0 + 6x 3 – 6x+12 = 2x 5 – 2x 3 + 4x 2 + 6x 3 – 6x+12 = 2x 5 + (-2+6)x 3 + 4x 2 – 6x+12 = 2x 5 + 4x 3 + 4x 2 – 6x+12. Atau kamu juga bisa coba dengan tabel seperti ini: Seperti yang sudah disinggung sebelumnya, pembagian suku banyak bisa menggunakan cara bersusun dan Horner. david's bridal orland park reviews Rearrange into the form: (x−4)2 +(y−3)2 = 22 to identify the centre (4,3) and radius 2 ... Find the equations of the circles that have centre (0,0) and touch the circle x2 + y2 − 8x − 6y + 24 = 0. This does not need calculus, just a theorem from euclidean geometry. The given circle has centre (4,3) and radius 1 unit.High School Math Solutions – Quadratic Equations Calculator, Part 1. A quadratic equation is a second degree polynomial having the general form ax^2 + bx + c = 0, where a, b, and c... Read More. Save to Notebook! Free quadratic equation calculator - Solve quadratic equations using factoring, complete the square and the quadratic formula step ... what is the client id for georgia gateway Similar Problems from Web Search. 6x2-5x-1=0 Two solutions were found : x = -1/6 = -0.167 x = 1 Step by step solution : Step 1 :Equation at the end of step 1 : ( (2•3x2) - 5x) - 1 = 0 Step 2 :Trying to factor by splitting ... 6 (-5)x2=1296 Two solutions were found : x = 1296 • ± √6 = ± 3174.5387 Reformatting the input : Changes made to ... apartments within 25 miles of me Algebra Solve by Factoring 2x^2-6x=0 2x2 − 6x = 0 2 x 2 - 6 x = 0 Factor 2x 2 x out of 2x2 −6x 2 x 2 - 6 x. Tap for more steps... 2x(x−3) = 0 2 x ( x - 3) = 0 If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. x = 0 x = 0 x−3 = 0 x - 3 = 0 Set x x equal to 0 0. x = 0 x = 0Solve Quadratic Equation by Completing The Square. 3.2 Solving 2x2-6x-1 = 0 by Completing The Square . Divide both sides of the equation by 2 to have 1 as the coefficient of the first term : x2-3x- (1/2) = 0. Add 1/2 to both side of the equation : x2-3x = 1/2. Now the clever bit: Take the coefficient of x , which is 3 , divide by two, giving 3/ ... weverse concert If a, b, and c are real numbers and a ≠ 0 then When b² − 4ac > 0, there are two distinct real roots or solutions to the equation ax² + bx + c = 0. When b² − 4ac = 0, there is one repeated real solution. When b² − 4ac < 0, there are two distinct complex solutions, which are complex conjugates of each other. Trinomial.Quadratic Equations in Vertex Form have a general form: #color(red)(y=f(x)=a(x-h)^2+k#, where #color(red)((h,k)# is the #color(blue)("Vertex"# Let us consider a quadratic equation in Vertex Form:great question. Let's use the equation 3s^2 + 6 + 1 = -1. With this you combine like terms so you would add 1 to the -1 to get the equation to equal 0. Because t is compatible with our 1 in the equation you would combine them because they are like terms. You then solve the equation like Sal explains. crown fine arts by carolina mirror 2x2-6x-16=0 Two solutions were found : x = (3-√41)/2=-1.702 x = (3+√41)/2= 4.702 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 - 6x) - 16 = 0 Step 2 : Step 3 ... 3x2-6x-16=0 Two solutions were found : x = (6-√228)/6=1-1/3√ 57 = -1.517 x = (6+√228)/6=1+1/3√ 57 = 3.517 Step by step solution : Step 1 :Equation at ... Click here👆to get an answer to your question ️ For what value of a, the roots of the equation 2x^2 + 6x + a = 0 , satisfy the conditions (alphabeta) + (betaalpha) < 2 (where beta,alpha are the roots of equation). usssa nebraska fastpitch Equation at the end of step 1 (2x2 - 6x) - 1 = 0 . STEP. 2: Trying to factor by splitting the middle term. 2.1 Factoring 2x2-6x-1 . The first term is, 2x2 its coefficient is 2 . The middle term is, -6x its coefficient is -6 . The last term, "the constant", is -1 . Step-1 : Multiply the coefficient of the first term by the constant 2 • -1 = -2 wmur tv 9 news Factor 2x+6. 2x + 6 2 x + 6. Factor 2 2 out of 2x 2 x. 2(x)+6 2 ( x) + 6. Factor 2 2 out of 6 6. 2x+2⋅3 2 x + 2 ⋅ 3. Factor 2 2 out of 2x+2⋅3 2 x + 2 ⋅ 3. 2(x+3) 2 ( x + 3) Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math ... hours for ups today Precalculus. Factor 2x^2+6x+1. 2x2 + 6x + 1 2 x 2 + 6 x + 1. 2x2 + 6x+1 2 x 2 + 6 x + 1. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. 4x2+6x+2=0 Two solutions were found : x = -1 x = -1/2 = -0.500 Step by step solution : Step 1 :Equation at the end of step 1 : (22x2 + 6x) + 2 = 0 Step 2 : Step 3 :Pulling out like ... How do you solve the equation 4x2 = 20x − 25 by completing the square? 25 Explanation: given, 4x2 = 20x−25 ⇒4x2−20x+25 = 0 ⇒(2x)2−2⋅2x⋅5 +(5)2 ...